correct math

git-svn-id: https://bucket.mit.edu/svn/nilm/zoom@6528 ddd99763-3ecb-0310-9145-efcb8ce7c51f

notes.txt

@@ -41,8 +41,8 @@ to account for that (we'll use 128).
 ---
 
 1 bit change on DAC is 600 μA
-LA-55 output voltage is x/1000 * 100 = 0.6 mV
-ADC input changes by x*11 = 6.6 mV
-which is a count of x / (2.50 / 2^12) = 10.8
-So to counteract a change of X on the ADC, change dac by (X/10.8).
+LA-55 output voltage is x/1000 * 100 = 0.06 mV
+ADC input changes by x*11 = 0.66 mV
+which is a count of x / (2.50 / 2^12) = 1.08
+So to counteract a change of X on the ADC, change dac by (X/1.08).